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=0.2Y^2+0Y+3
We move all terms to the left:
-(0.2Y^2+0Y+3)=0
We get rid of parentheses
-0.2Y^2-0Y-3=0
We add all the numbers together, and all the variables
-0.2Y^2-1Y-3=0
a = -0.2; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·(-0.2)·(-3)
Δ = -1.4
Delta is less than zero, so there is no solution for the equation
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